Using select with -e: exit code only depends on last item

[pswaminathan]

Describe the bug
Using select, the exit code when using the -e flag depends only on the last item processed, not any item.

To Reproduce

$ echo '{"some": "out", "success": true}\n{"some": "out", "success": false}' | jq -e 'select(.success)' 1>/dev/null; echo $?
4

$ echo '{"some": "out", "success": false}\n{"some": "out", "success": true}' | jq -e 'select(.success)' 1>/dev/null; echo $?
0

Expected behavior
Both of the above lines produce the same output (when run without the output flags):

$ echo '{"some": "out", "success": true}\n{"some": "out", "success": false}' | jq -e 'select(.success)'
{
  "some": "out",
  "success": true
}

I would expect the exit code to be 0 for both, as valid output was produced. Instead, the exit codes differ depending on whether or not the last item produced a valid output.

Environment (please complete the following information):

• OS and Version: macOS Monterey 12.6.1
• jq version 1.6

Additional context
N/A

[wader]

Hi, could you try jq master? brew install --HEAD jq if your using homebrew. I suspect this might be fixed by #1697 that was merged after jq 1.6

[pswaminathan]

Yes, that fixed it! I tried to look for open issues first. Seems I didn't search effectively enough, as I didn't see the issue that fixed. Thanks for your help!

[wader]

@pswaminathan 👍 no problem, hope there will be new release eventually